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x^2+5x=696
We move all terms to the left:
x^2+5x-(696)=0
a = 1; b = 5; c = -696;
Δ = b2-4ac
Δ = 52-4·1·(-696)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-53}{2*1}=\frac{-58}{2} =-29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+53}{2*1}=\frac{48}{2} =24 $
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